Question 331857
Two integers, x, (x+2)
:
If the difference between the squares of two consecutive even integers is
 the same as four less then the product of the integers
(x+2)^2 - x^2 = x(x+2) - 4
:
x^2 + 4x + 4 - x^2 = x^2 + 2x - 4
:
4x + 4 = x^2 + 2x - 4
:
0 = x^2 + 2x - 4x - 4 - 4
Solve a quadratic equation
x^2 - 2x - 8 = 0
Factors to
(x-4)(x+2) = 0
Two solutions
x = 4, 6 are the two integers they want
and
x = -2, 0; not sure if these qualify
:
:
See if this flies
4, 6
6^2 - 4^2 = 4(6) - 4
36 - 16 = 24 - 4; OK
and
-2, 0
0 - 4 = 0 - 4;