Question 38295
To find the vertex, comlpete the square.
Using intercepts; y=0
{{{0=3x^2-12x+16}}}
{{{3(x^2-4x)+16=0}}}
{{{3(x^2-4x+4-4)+16=0}}}
{{{3(x^2-4x+4)-12+16=0}}}
{{{3(x-2)^2+4=0}}}
Vertex:
(2,4)
Paul.