Question 331621
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I can't see where you got the idea that you want to multiply by *[tex \Large \frac{1}{4}].  Follow the procedure below:


Solve this one by substitution.


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ xy\ =\ 1\ \ \Rightarrow\ \ y\ =\ \frac{1}{x}]


Then substitute in the second equation:


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ 2x\ -\ \frac{1}{x}\ =\ 1]


Multiply both sides by *[tex \Large x]


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ 2x^2\ -\ 1\ =\ x]


Put in standard form and then solve the quadratic for *[tex \Large x]


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ 2x^2\ -\ x\ -\ 1\ =\ 0]


Then substitute each of the values of *[tex \Large x] back into the original first equation to determine each of the associated values of *[tex \Large y].


John
*[tex \LARGE e^{i\pi} + 1 = 0]
My calculator said it, I believe it, that settles it
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