Question 331584
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Step 1:  Solve the given equation for *[tex \Large y] in terms of everything else.  That is to say, put it into slope-intercept form, *[tex \Large y\ =\ mx\ +\ b].


Step 2:  Determine the slope of the given line by examination of the coefficient on *[tex \Large x].  The slope of the desired line will be equal because:


*[tex \LARGE \ \ \ \ \ \ \ \ \ \  L_1\ \parallel\ L_2 \ \ \Leftrightarrow\ \ m_1\ =\ m_2]


Step 3:  Use the point-slope form of the equation of a straight line:


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ y\ -\ y_1\ =\ m(x\ -\ x_1) ]


where *[tex \Large \left(x_1,y_1\right)] are the coordinates of the given point and *[tex \Large m] is the given/calculated slope.


John
*[tex \LARGE e^{i\pi} + 1 = 0]
My calculator said it, I believe it, that settles it
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