Question 331444
{{{(x-3)^2+3x^2-5x=12}}}

x^2-6x+9+3x^2-5x-12=0
4x^2-11x-3=0
4x^2-12x+x-3=0
4x(x-3)+1(x-3)=0
(x-3)(4x+1)=0
x=3 OR x=-1/4