<PRE><B>Question 331356</B>
x^2+3x=4
x^2+3x-4=0
(x+4)(x-1)=0
x+4=0
x=-4 ans.
x-1=0
x=1 ans.
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4x^2-3x=-6 
4x^2-3x+6=0
{{{x = (-b +- sqrt( b^2-4*a*c ))/(2*a) }}} 
X=(3+-SQRT[-3^2-4*4*6])/2*4
X=(3+-SQRT[9-96])/8
X=(3+-SQRT-87)/8
X=(3+-9.327i)/8
X=3/8+-9.327i/8
X=.375+-1.166i</PRE>