Question 331217
Find the third term in the expansion of {{{(2x-3y)^8}}} 
<pre><b>
The kth term in the expansion of {{{(A+B)^n}}} is given
by the formula:

{{{(matrix(2,1,n,r-1))*A^(n-r+1)*B^(r-1)}}} or sometimes it's written {{{C(n,r-1)*A^(n-r+1)*B^(r-1)}}}

In your problem,

{{{A=2x}}}, {{{B=-3y}}}, {{{n=8}}}, {{{r=3}}}

So we substititute:

{{{(matrix(2,1,8,3-1))*(2x)^(8-3+1)*(-3y)^(3-1)}}} or {{{C(8,3-1)*(2x)^(8-3+1)*(-3y)^(3-1)}}}

{{{(matrix(2,1,8,2))*(2x)^6*(-3y)^2}}} or {{{C(8,2)*(2x)^6*(-3y)^2}}}

{{{((8*7)/(2*1))*2^6*x^6*(-3)^2y^2}}}

{{{(56/2)*64*x^6*9y^2}}}

{{{28*64*9*x^6*y^2}}}

{{{16128x^6y^2}}}

Edwin</pre>