Question 331177
SOLVE
Assume the expression is:
{{{(x^2-y^2)/(z-x)}}} where x=-3, y=5, and z=-1
Just substitute the given values for the variables
{{{(-3^2-5^2)/(-1-(-3))}}}
minus a minus, is a plus, minus times a minus is plus also
{{{(-3^2-(-5^2))/(-1+3)}}} = {{{(9-(+25))/(2)}}} = {{{(-16)/2}}} = -8