Question 331106
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You were doing great until you got a little balled up trying to simplify *[tex \Large \sqrt{300}]


Go back one step:


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ \frac{\sqrt{25}\,\cdot\,\sqrt{12}}{\sqrt{12}\,\cdot\,\sqrt{12}}]


Do the denominator but leave the numerator alone for the moment:


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ \frac{\sqrt{25}\,\cdot\,\sqrt{12}}{12}]


Now, *[tex \Large \sqrt{25}\ =\ 5], so:


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ \frac{5\,\cdot\,\sqrt{12}}{12}]


And since *[tex \Large 12\ =\ 3\,\cdot\,4], we can write:


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ \frac{5\,\cdot\,\sqrt{4}\,\cdot\,\sqrt{3}}{12}\ =\ \frac{10\,\cdot\,\sqrt{3}}{12}]


and we're done.





John
*[tex \LARGE e^{i\pi} + 1 = 0]
My calculator said it, I believe it, that settles it
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