Question 330783
In 1991 the life expectancy of males in a certain country was 63.2 years.
 In 1996 it was 65.7 years.
:
Find the slope
In 1991; x1=0 and y1=63.2
In 1996; x2=5 and y2=65.7
:
Find the slope (m) using the slope equation: m = {{{(y2-y1)/(x2-x1)}}}
m = {{{(65.7-63.2)/(5 - 0))}}} = {{{(2.5)/(5)}}} = .5
:
Use the point/slope formula to write the equation; y - y1 = m(x - x1)
y - 63.2 = .5(x - 0)
y = .5x + 63.2
:
Let E represent the life expectancy in year t, and let t represent the number of years since 1991.
E(t) = .5t + 63.2, The linear function E(t) that fits the data 
:
Use the function to predict the life expectancy of males in 2006.
E(15)= .5(15) + 63.2 round to the nearest tenth.
E(15) = 7.5 + 63.2
E(15) = 70.7 life expectancy in 2006