Question 330987
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The zero product rule says that *[tex \Large ab\ =\ 0] if and only if *[tex \Large a\ =\ 0] or *[tex \Large b\ =\ 0]


So, either *[tex \Large 9c\ +\ 5\ =\ 0] or *[tex \Large 4c\ -\ 12\ =\ 0]


Solve for *[tex \Large c] in each case and the solution set will consist of both values of *[tex \Large c]


John
*[tex \LARGE e^{i\pi} + 1 = 0]
My calculator said it, I believe it, that settles it
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