Question 330857
Solve
f(x) = x^2 - 8x + 16 = 0
{{{(x-4)^2 =0}}}
(x-4) = 0
x = 4
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x=4 is the minimum value of the function, f(x) = 0
For all other values, f(x) > 0
--> For all x, f(x) >= 0
--> All x