Question 330858
{{{x^2 -4x + 4= -x^2 + 6x - 8}}}
{{{2x^2-10x+12=0}}}
{{{x^2-5x+6=0}}}
{{{(x-2)(x-3)=0}}}
Two solutions:
{{{x-2=0}}}
{{{x=2}}}
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{{{x-3=0}}}
{{{x=3}}}
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Now use either equation to solve for y.
{{{x=2}}},{{{y=2^2-4(2)+4=0}}}:(2,0)
{{{x=3}}},{{{y=3^2-4(3)+4=1}}}:(3,1)
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{{{drawing(300,300,-2,8,-4,4,grid(1),circle(2,0,.2),circle(3,1,.2),graph(300,300,-2,8,-4,4,x^2-4x+4,-x^2+6x-8))}}}