Question 330858
Assuming Q1 is: {{{y=x^2-4x+4}}},
using equation rule: {{{(a-b)^2=a^2-2ab+b^2}}},
{{{y=x^2-4x+4}}}
y = (x-2)(x-2)

Q2:
{{{y=-x^2+6x-8}}}
y=(-x+4)(x-2)