Question 330768
Point A(-4,1) is in the standard (x,y) coordinate plane. 
What must be the coordinates of point B so that the line x=2 is the perpendicular bisector of AB?"
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Plot the point (-4,1)
Draw the line x = 2
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Notice that the line passes thru (2,1)
That point is the midpoint of AB
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Let (x,y) be the coordinates of "B".
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Solve for x and for y:
(x+(-4))/2 = 2
x-4 = 4
x = 8
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(y+1)/2 = 1
y+1 = 2
y = 1
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The coordinates of "B" are(8,1)
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Cheers,
Stan H.