Question 330582
{{{2sin^2(x)=cos(x)+1}}}
{{{2(1-cos^2(x))=cos(x)+1}}}
{{{2-2cos^2(x)-cos(1)-1=0}}}
{{{-2cos^2(x)-cos(1)+1=0}}}
{{{2cos^2(x)+cos(1)-1=0}}}
{{{(2cos(x)-1)(cos(x)+1)=0}}}
Solve both:
{{{2cos(x)-1=0}}}
{{{cos(x)=1/2}}}
{{{x=60}}}degrees and {{{x=300}}}degrees
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{{{cos(x)+1=0}}}
{{{ cos(x)=-1 }}}

{{{x=180}}}degrees
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Three solutions: {{{60}}},{{{180}}},{{{300}}} degrees ({{{pi/3}}},{{{pi}}},{{{5pi/3}}}) radians