Question 330459
{{{2x-5y=20}}}
{{{-5y=-2x+20}}}
{{{y=(2/5)x-4}}}
Perpendicular lines have slopes that are negative reciprocals.
{{{m1*m2=-1}}}
{{{(2/5)*m2=-1}}}
{{{m2=-5/2}}}
{{{y=-(5/2)x+b}}}
Since it can be any line let {{{b=0}}}.
{{{highlight(y=-(5/2)x)}}}
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Parallel lines have the same slope and different intercept.
{{{highlight(y=(2/5)x)}}}
Plot them all together.
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{{{graph(300,300,-10,10,-10,10,(2/5)x-4,-(5/2)x,(2/5)x)}}}