Question 330520
Let D be the number of dimes, Q the number of quarters.
1.{{{D+Q=93}}}
2.{{{10D+25Q=1095}}}
From eq. 1,
{{{D=93-Q}}}
Substitute into eq. 2,
{{{10(93-Q)+25Q=1095}}}
{{{930-10Q+25Q=1095}}}
{{{15Q=165}}}
{{{Q=11}}}
From eq. 1,
{{{D+11=93}}}
{{{D=82}}}
There are 82 dimes and 11 quarters.