Question 330528
x^2 + 52 = 8x
x^2-8x+52=0
{{{x1=(-b+sqrt(b^2-4*a*c))/2a}}}
a=1,b=-8,c=52
{{{x1=(8+sqrt(64+4*1*52))/2}}}
x1=12.25
..
x2={{{x1=(8-sqrt(64+4*1*52))/2}}}
x2= 4.25