Question 330492
half of henry's age added to one-third of daisy's age is 11 years. Six years from now, the sum of their ages will be 40 years. how old is each?

let h=henry's age, d=daisi's

1) h/2+d/3=11
2) (h+6)+(d+6)=40 => h+d=28 => h=28-d

->1 : 14-d/2+d/3=14-d/6=11 => d/6=3 => d=18 years=daisi's age

henry's age h=28-18=10 years