Question 330433
Solve:
{{{2x-5 = sqrt(7x+7)}}} Square both sides.
{{{4x^2-20x+25 = 7x+7}}} Subtract 7x from both sides.
{{{4x^2-27x+25 = 7}}} Subtract 7 from both sides.
{{{4x^2-27x+18 = 0}}} Solve using the quadratic formula:{{{x = (-b+-sqrt(b^2-4ac))/2a}}} and here, a = 4, b = -27, and c = 18.
You can work this out but I get the answers: x = 6 or x = 0.75