Question 330407
I'll do the first one to get you started



Let's find the slope of the line passing through the points *[Tex \LARGE P\left(3,7\right)] and *[Tex \LARGE Q\left(6,16\right)]
 


Note: *[Tex \LARGE \left(x_{1}, y_{1}\right)] is the first point *[Tex \LARGE \left(3,7\right)]. So this means that {{{x[1]=3}}} and {{{y[1]=7}}}.

Also, *[Tex \LARGE \left(x_{2}, y_{2}\right)] is the second point *[Tex \LARGE \left(6,16\right)].  So this means that {{{x[2]=6}}} and {{{y[2]=16}}}.



{{{m=(y[2]-y[1])/(x[2]-x[1])}}} Start with the slope formula.



{{{m=(16-7)/(6-3)}}} Plug in {{{y[2]=16}}}, {{{y[1]=7}}}, {{{x[2]=6}}}, and {{{x[1]=3}}}



{{{m=(9)/(6-3)}}} Subtract {{{7}}} from {{{16}}} to get {{{9}}}



{{{m=(9)/(3)}}} Subtract {{{3}}} from {{{6}}} to get {{{3}}}



{{{m=3}}} Reduce



So the slope of the line that goes through the points *[Tex \LARGE P\left(3,7\right)] and *[Tex \LARGE Q\left(6,16\right)] is {{{m=3}}}