Question 330340
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Sorry to disappoint, but this has nothing whatever to do with the distributive property.


This is a relative rate problem.  Since one of them is going 80 and the other 60 they are going 140 relative to each other.  They have 60 miles to cover together, so the elapsed time when they meet is the distance divided by the rate, or 60 divided by 140, which is to say *[tex \Large \frac{3}{7}] hour.  Since Chris is going 60, he has traveled *[tex \Large \frac{3}{7}\ \times 60\ \approx 25.7] miles and he has accomplished this feat in *[tex \Large \frac{3}{7}\ \times 60\ \approx 25.7] minutes.  So if they left at 2:00 pm it is 2:25.7 when they meet -- IF AND ONLY IF Annette didn't get stopped and cited for going 80 mph in a 65 mph zone.



John
*[tex \LARGE e^{i\pi} + 1 = 0]
My calculator said it, I believe it, that settles it
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