Question 330347
when a ball is thrown, it's [sic] height in feet H after t seconds is given by the equation h=vt-16t^2 where v is the initial upwards velocity in feet per second if v=13 feet per second find all the values of t for which h=2
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h(t) = vt-16t^2
Sub 2 for h and 13 for h
2 = 13t - 16t^2
16t^2 - 13t + 2 = 0
*[invoke solve_quadratic_equation -16,13,-2]
t = x
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It's at 2 feet twice, going up, then coming back down.
Most people find it difficult to throw a ball straight up from ground level.