Question 330297
1.{{{x^2+y^2 =25}}}
.
.
.
2.{{{y-x =-1}}}
{{{y=x-1}}}
{{{y^2=(x-1)^2}}}
Substitute into eq. 1,
{{{x^2+(x-1)^2=25}}}
{{{x^2+x^2-2x+1=25}}}
{{{2x^2-2x-24=0}}}
{{{x^2-x-12=0}}}
{{{(x-4)(x+3)=0}}}
Two solutions:
{{{x-4=0}}}
{{{x=4}}}
.
.
.
{{{x+3=0}}}
{{{x=-3}}}
.
.
.
For each x solve for y.
{{{y=x-1}}}
{{{x=4}}}, {{{y=3}}}(4,3)
{{{x=-3}}},{{{y=-4}}}(-3,-4)
.
.
.
{{{drawing(300,300,-6,6,-6,6,grid(1),circle(4,3,.2),circle(-3,-4,.2),graph(300,300,-6,6,-6,6,x-1,sqrt(25-x^2)),graph(300,300,-6,6,-6,6,x-1,-sqrt(25-x^2)))}}}