Question 330250
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I think you are trying to render:


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ \left(\frac{2x^3y^{-3}}{x^{-2}y^3\right)^{-5}]


And you didn't say, but the only thing I can think you might want is to simplify this, so:


Move negative exponent items from numerator to denominator and vice versa (leave the -5 exponent alone for the time being).  The negative exponents become positive when they move, and then you just add the exponents for like variables.


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ \left(\frac{2x^5}{y^6\right)^{-5}]


Now remove the negative sign from the -5 exponent and invert the fraction inside the parentheses:


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ \left(\frac{y^6}{2x^5\right)^{5}]


Raising a power to a power, multiply the exponents:


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ \frac{y^{30}}{2x^{25}]


To the extent that I rendered your problem as you intended, you should have written:


((2x^3y^(-3))/(x^(-2)y^3))^(-5).


Furthermore, next time tell us what it is that you actually want, and what is giving you trouble.  This is Algebra.com, not the Psychic Hot Line.



John
*[tex \LARGE e^{i\pi} + 1 = 0]
My calculator said it, I believe it, that settles it
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