Question 330139
{{{k(x)=sqrt(x+1)}}}
I'll do one, you do the rest.
{{{k(x)=sqrt(x+1)}}}
{{{k(-3)=sqrt(-3+1)}}}
{{{k(-3)=sqrt(-2)}}}
Since {{{sqrt(-2)}}} is not defined, the answer is undefined.
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Use the same method to get the other values unless they're undefined.
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b) The domain is all x for which the function is defined.
The square root function requires non-negative arguments.
{{{k+1>=0}}}
{{{k>=-1}}}
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({{{-1}}},{{{infinity}}})
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c)
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{{{graph(300,300,-3,10,-6,6,sqrt(x+1))}}}