Question 330260
{{{((3b^2 - 12)/(6b^2 + 12b))((5b -10)/(10b^2 + 20b))=((3(b-2)(b+2))/(6b(b+2)))*((5(b-2))/(10(b + 2)))}}}
{{{((3b^2 - 12)/(6b^2 + 12b))((5b -10)/(10b^2 + 20b))=(((b-2)*cross((b+2)))/(2b*cross((b+2))))*(((b-2))/(2(b + 2)))}}}
{{{((3b^2 - 12)/(6b^2 + 12b))((5b -10)/(10b^2 + 20b))=(b-2)^2/(4b(b+2))}}}