Question 330227
{{{2log((a))=log((b))}}}
{{{log((a^2))=log((b))}}}
{{{b=a^2}}}
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{{{5log((a))=log((c))}}}
{{{log((a^5))=log((c))}}}
{{{c=a^5}}}
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{{{a^4*b^3*c^(-2)=a^4*a^2*a^(-10)}}}
{{{a^4*b^3*c^(-2)=a^(4+2-10)}}}
{{{a^4*b^3*c^(-2)=a^(-4)}}}
{{{a^4*b^3*c^(-2)=1/a^4}}}