Question 330205
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An object in free-fall near the Earth's surface, presuming that you discount the effects of friction with the atmosphere, has a vertical displacement in feet as a function of time in seconds given by:


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ h(t)\ =\ 16t^2]


All you have to do is evaluate *[tex \LARGE h(8)].  Note that this is NOT the same thing as how far the object fell during the 8th second.  That value would be calculated by *[tex \LARGE h(8) - h(7)].  *[tex \LARGE h(n) - h(n\ -\ 1)] was the methodology to calculate the sequence of values you gave.
 

John
*[tex \LARGE e^{i\pi} + 1 = 0]
My calculator said it, I believe it, that settles it
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