Question 330197
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Height as a function of time for a projectile propelled straight up near the Earth's surface is given by:



*[tex \LARGE \ \ \ \ \ \ \ \ \ \ h(t)\ =\ -16t^2\ +\ v_ot\ +\ h_o]


Your problem gives initial velocity:  *[tex \Large 16] ft/sec.


Your problem gives initial height:  *[tex \Large 12] ft.


You want to determine the value of *[tex \Large t] when *[tex \Large h(t)\ =\ 0] and *[tex \Large t\ >\ 0].


Simply solve the quadratic equation:


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ -16t^2\ +\ 16t\ +\ 12\ =\ 0]


And discard the negative root.


<i><b>Super Double Plus Special Extra Credit</b></i>


Interpret the meaning of the negative root to the equation and explain why it needs to be discarded.


John
*[tex \LARGE e^{i\pi} + 1 = 0]
My calculator said it, I believe it, that settles it
<img src="http://c0rk.blogs.com/gr0undzer0/darwin-fish.jpg">
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