Question 330057
1.{{{5N+10D+25Q=855}}}
2.{{{D=N+Q+7}}}
Substituting eq. 2 into eq. 1,
{{{5N+10N+10Q+70+25Q=855}}}
{{{15N+35Q=785}}}
{{{3N+7Q=157}}}
There are multiple solutions because you have 1 equation with 2 unknowns.
1 nickels, 22 quarters, (19+4+7=)30 dimes
8 nickels,19 quarters, 34 dimes
15 nickels,16 quarters, 38 dimes
22 nickels,13 quarters, 42 dimes
29 nickels,10 quarters, 46 dimes
36 nickels,7 quarters, 50 dimes
43 nickels,4 quarters, 54 dimes
50 nickels,1 quarters, 58 dimes