Question 330046
Do you mean {{{(40q^8)/(48q^12)}}}?
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{{{(40q^8)/(48q^12)=(5*8*q^8)/(6*8*q^4*q^8)}}}
{{{(40q^8)/(48q^12)=(5*cross(8)*cross(q^8))/(6*cross(8)*q^4*cross(q^8))}}}

{{{(40q^8)/(48q^12)=5/(6q^4)}}}