Question 330126
This is a quadratic equation in {{{x^2}}} and not {{{x}}}. 
Solve it by factoring.
{{{10x^4-17x^2+3=(5x^2-1)(2x^2-3)=0}}}
Four solutions:
{{{5x^2-1=0}}}
{{{5x^2=1}}}
{{{x^2=1/5}}}
{{{highlight(x=0 +- sqrt(5)/5)}}}
.
.
.
{{{2x^2-3=0}}}
{{{2x^2=3}}}
{{{x^2=3/2}}}
{{{highlight(x=0 +- (3sqrt(2))/2)}}}