<PRE><B>Question 330078</B>
    The perimeter of a basketball court is 280 ft. The length is 44 ft longer than the width. Find the dimension of the court
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Let L = length
and W = width
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Then,
2(L+W) = 280 (equation 1)
L = W + 44  (equation 2)
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Substitute the value of L from equation 2 into equation 1 to solve for W:
2(L+W) = 280
2(W+44+W) = 280
2(2W+44) = 280
2W+44 = 140
2W = 96
W = 48 feet (width)
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Length:
W + 44 = 48 + 44 = 92 feet
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Dimension: 48 by 92 feet</PRE>