Question 329967
{{{(x^2 - 4x + 4)/(2x^2 - 3x - 2 )=(x-2)^2/((2x+1)(x-2))}}}
{{{(x^2 - 4x + 4)/(2x^2 - 3x - 2 )=(x-2)/(2x+1)}}}
The denominator equals zero when
{{{2x+1=0}}}
{{{2x=-1}}}
{{{x=-1/2}}}