Question 329903
{{{(7+3i)/(4-2i)}}}
Multiply the equation by the conjugate of the denominator over itself
{{{(7+3i)/(4-2i)}}} * {{{(4+2i)/(4+2i)}}} = {{{(28+ 14i+12i+ 6i^2)/(16 - 4i^2)}}} = {{{(28 + 26i + 6(-1))/(16 - 4(-1))}}} = {{{(28 + 26i - 6)/(16 + 4)}}} = {{{(22 + 26i)/20}}}
{{{22/20}}} + {{{(26i)/20}}} = {{{11/10}}} + {{{(13i)/10}}} = 1.1 + 1.3i