<PRE><B>Question 329827</B>
 Of 100 students, 37 play an instrument, 45 play sports, and 11 do both. What is the probability that a student neither plays an instrument nor plays sports?
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P(instru or sports) = P(instru)+P(sports)-P(both) = [37+45-11]/100 
= 71/100
P(not(instru or sports)) = 1-71/100 = 29/100
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Cheers,
Stan H.
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(A) 0.145 (B) 0.18 (C) 0.29 (D) 0.40 (E) 0.82
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