Question 329732
Keiko bicycles 5 km/h faster than Praedup.  In the same time it takes praedup to bicycle 54 km, Keiko can bicycle 69 km.  How fast does each bicyclist travel?

Praedup travels ______ km/h.

Keiko travels  ________  km/h.

..
let Praedup rate be x
Keiko's rate = x+5 
..
time taken by Praedup = 54/x
time taken by Keiko = 69/(x+5)
54/x = 69/(x+5)
69x=54(x+5)
69x=54x+270
69x-54x=270
15x=270
x=270/15
x=18km/h ---- Praedup's rate
Keiko's rate = x+5 , = 18+5=23 km/h