<PRE><B>Question 329761</B>
Given a mean of 120 and a standard deviation of 5.5, 
find the 95th percentile.
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Find the z-value with a left tail of 0.95.
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invNorm(0.95) = 1.645
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Use x = zs+u to find the 95th% score.
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x = 1.645*5.5+120 = 129.05
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Cheers,
Stan H. 
</PRE>