Question 329725
2n^2 + 3n -1
{{{n = (-b +- sqrt( b^2-4*a*c ))/(2*a) }}} 
n=(-3+-sqrt[3^2-4*2*-1])/2*2
n=(-3+-sqrt(9+8])/4
n=(-3+-sqrt17)/4
n=(-3+-4.1231)/2
n=(-3+4.1231)/4
n=1.1231/4
n=.28 ans.
n=(-3-4.1231)/4
n=-7.1231/4
n=--1,78 ans.
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2m^2 + 10m = -12
2m^2+10m+12=0
2(m^2+5m+6)=0
2(m+3)(m+2)=0
m+3=0
m=-3 ans.
m+2=0
m=-2 ans.
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2x^2 + 5x -3 =0
(2x-1)(x+3)=0
2x-1=0
2x=1
x=1/2 ans.
x+3=0
x=-3 ans.