Question 329669
[w-7/w-3] = [w-7/w-4] +1
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Multiply thru by (w-3)(w-4) to get:
(w-4)(w-7) = (w-3)(w-7) + (w-3)(w-4)
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w^2-11w+28 = w^2-10w+21 + w^2-7w+12

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w^2-6w +5 = 0
Factor:
(w-5)(w-1) = 0
w = 5 or w = 1
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Cheers,
Stan H.
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