Question 329620
Find the value of "a" if a line containing the point (a,-2a) has a y-intercept of 6 and slope of -2/3.
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Using slope and intercept info you get:
y = (-2/3)x+6
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Using the point info you get:
-2a = (-2/3)a+6
Multiply thru by 3 to get:
-6a = -2a + 18
Solve for "a":
4a = -18
a = -9/2
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Cheers,
Stan H.
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