Question 329514
1.{{{2x^2-y^2+7= 0}}}
2.{{{3x^2-4y^2+33=0}}}
From eq. 1,
{{{y^2=2x^2+7}}}
{{{4y^2=8x^2+28}}}
Substitute into eq. 2,
{{{3x^2-8x^2-28+33=0}}}
{{{-5x^2+5=0}}}
{{{x^2=1}}}
{{{x=0 +- 1}}}
.
.
.
For each x, find the y value.
{{{y^2=2x^2+7}}}
{{{y^2=2+7}}}
{{{y=0 +- 3}}}
(1,3),(1,-3),(-1,3),(-1,-3)
.
.
.
{{{drawing(300,300,-5,5,-5,5,grid(1),circle(1,3,.2),circle(1,-3,.2),circle(-1,3,.2),circle(-1,-3,.2),graph(300,300,-5,5,-5,5,sqrt(2x^2+7),sqrt((3x^2+33)/4)),graph(300,300,-5,5,-5,5,-sqrt(2x^2+7),-sqrt((3x^2+33)/4)))}}}