Question 329550
{{{graph(300,300,-1,1,-2,1,x^3-x^2-x-1)}}}
{{{f(x)=x^3-x^2-x-1}}}
{{{df/dx=3x^2-2x-1=0}}}
{{{(3x+1)(x-1)=0}}}
Two solutions:
{{{x-1=0}}}
{{{x=1}}}
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.
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{{{3x+1=0}}}
{{{3x=-1}}}
{{{x=-1/3}}}
The max. value occurs at {{{x=-1/3}}}.
{{{f(-1/3)=-1/27-1/9+1/3-1}}}
{{{f(-1/3)=-22/27}}}