Question 329544
from lightest to heaviest , let the bales be a , b , c , d , and e


a + c = 112 ___ a = 112 - c


the two lightest ___ a + b = 110 ___ b = 110 - a = c - 2


c + e = 120 ___ e = 120 - c


the two heaviest ___ d + e = 121 ___ d = 121 - e = c + 1


each bale is weighed twice ___ a + b + c + d + e = (110 + 112 + 113 + 114 + 115 + 116 + 117 + 118 + 120 + 121) / 2


substitute to find c , then substitute back to find the others