Question 329552
 How do I factor the difference of cubes in this expression: 
27n^3-64
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= (3n)^3 - 4^3
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= (3n-4)((3n)^2 +(3n)(4) + 4^2)
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= (3n-4)(9n^ + 12n + 16)
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Cheers,
Stan H.