Question 329482
Look at 3 possibilities: 
First card is a spade, second isn't
Second card is a spade, first isn't
Both cards are spades.
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.
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P(spade, not spade)={{{(13/52)(39/51)}}}
P(not spade, spade)={{{(39/52)(13/51)}}}
P(spade,spade)={{{(13/52)(12/51)}}}
P(at least one spade)=P(spade,not spade)+P(not spade,spade)+P{spade,spade)
P(at least one spade)={{{1170/2652=585/1326=0.441}}}