Question 329443
{{{(6x^3+13x^2-11x-15)/(3x^2-x-3)}}}
First term : {{{2x}}}
{{{(2x)(3x^2-x-3)=6x^3-2x^2-6x}}}
Subtract this product from the original polynomial to get the remainder,
{{{(6x^3+13x^2-11x-15) -(6x^3-2x^2-6x)=15x^2-5x-15}}}
Second term : {{{5}}}
{{{(5)(3x^2-x-3)=15x^2-5x-15}}}
Subtract this product from the remainder to get the new remainder,
{{{(15x^2-5x-15)-(15x^2-5x-15)=0}}}
Collect the terms,
{{{(6x^3+13x^2-11x-15)/(3x^2-x-3)=(2x+5)}}}