Question 329446
When a parabola as its axis parallel to the y-axis and is concave up, it has equation {{{(x-h)^2=4p(y-k)}}}

where (h,k) are the vertex coordinates.

p is the distance from the vertex to the focus or from the vertex to the directrix. Thus, the distance from the focus to the directrix is 2p.

Since the y-coordinate of the focus is 6 and the directrix is at y=4, the distance between the focus and directrix is 2 units. This means 2p=2,
p=1

So, the focus coordinates (the h,k in the formula) are (10,5)

So, we have {{{(x-10)^2=4(y-5)}}}

{{{y=x^2/4-5x+30}}}

is the parabola equation